# How do you solve #4e^(9x-1)=64#?

##### 1 Answer

Mar 8, 2016

#### Explanation:

Divide both sides of the equation first. This will deal with the

#e^(9x-1)=16#

Now, take the natural logarithm of both sides of the equation.

#ln(e^(9x-1))=ln(16)#

Note that the

#9x-1=ln(16)#

Solving through basic algebra,

#x=(ln(16)+1)/9#